simple math work.......................................

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A 54-dB sound wave strikes an eardrum whose area is 5.0*10^-5m^2 . The intensity of the reference level required to determine the sound level is 1.0*10^-12W/m^2.1 year=3.156*10^7s .

a.How much energy is absorbed by the eardrum per second?
b.At this rate, how long would it take the eardrum to receive a total energy of 1.0 J ?
Jul 24th, 2015

Thank you for the opportunity to help you with your question!

3) a) energy/sec = power = E = I*A = 10^-12*5*10^-5 = 5*10^-7 W

b) time = E/P = 1/(5*10^-7) = 2e+6s frown emoticon 2*10^6 )/(3.156*10^7)= 63.3713561e?3 years


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Jul 24th, 2015

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