Newton's Method to find an approximate answer..

Calculus
Tutor: None Selected Time limit: 1 Day

Jul 24th, 2015

Thank you for the opportunity to help you with your question!

This is the starting approximate value to the largest zero. You might decide to take another value as long as it is close to the zero you are approximating.

We now calculate x1 using the above procedure for n = 0 as follows:

x1 = x0 - f(x0) / f '(x0)

Substitute x0 by its value 0 and calculate x1

x1 = 0 - f(0) / f '(0)

= - ((0) 2 + (0)x + 1) / (2(0) + 3)

= -1/3

We now calculate x2 as follows

x2 = x1 - f(x1) / f '(x1)

x2 = -1/3 - f(-1/3) / f '(-1/3) ≈ -0.38095238

We now calculate x3 as follows

x3 = x2 - f(x2) / f '(x2)

x3 ≈ -0.38196555

Continue with the procedure to find

x4 ≈ -0.38196601

x5 ≈ -0.38196601


Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 24th, 2015

Incorrect Answer :(

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Jul 24th, 2015

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