Find the area of the region under the graph of the function f on the interval

Calculus
Tutor: None Selected Time limit: 1 Day

Jul 28th, 2015

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intergrate first Area = 2.5x^2-x^3/3

now substitute limits  [ 2.5 * 5^2 - 5^3/3] - 0 = 20.833 sq units   (Answer)

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Jul 28th, 2015

hi it is saying this answer is incorrect 

Jul 28th, 2015

hi it is saying this answer is incorrect 

Jul 28th, 2015

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Jul 28th, 2015
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Jul 28th, 2015
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