Help with me make study guide

Biology
Tutor: None Selected Time limit: 1 Day

Gel Electrophoresis: PCR of Alu Gene

Understand the process / procedure to analyze / interpret the results of the PCR of Alu gene experiment.

Jul 28th, 2015

Thank you for the opportunity to help you with your question!

 

This examination looks at PV92, a human-particular Alu insertion on chromosome 16. The PV92 hereditary framework has just two alleles demonstrating the vicinity (+) or nonattendance (- ) of the Alu transposable component on each of the combined chromosomes. This outcomes in three PV92 genotypes (++, +-, or - ). The + and - alleles can be isolated by size utilizing gel electrophoresis. 

Alu components are delegated SINEs, or Short INterspersed Elements. All Alus are give or take 300 bp long and get their name from a solitary acknowledgment site for the limitation protein AluI situated close to the center of the Alu component. Human chromosomes contain around 1,000,000 Alu duplicates, which approach 10% of the aggregate genome. Alu components most likely emerged from a quality that encodes the RNA segment of the sign acknowledgment molecule, which names proteins for fare from the cell. 

Alu is a sample of a purported "hopping quality" – a transposable DNA grouping that "imitates" by duplicating itself and embeddings into new chromosome areas. Alu is named a retroposon, in light of the fact that it is thought to require the retrovirus catalyst reverse transcriptase (rt) chemical to make a versatile duplicate of itself. Here is a basic plan to clarify how an Alu component transpose

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 28th, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Jul 28th, 2015
...
Jul 28th, 2015
Dec 8th, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer