# Algebra

**Question description**

**I
will post an example of # 3 and instructions for the ac method at the
bottom**

For problems 1 and 2 factor the polynomials using whatever strategy seems appropriate. State what methods you will use and then demonstrate the methods on your problems, explaining the process as you go. Discuss any particular challenges those particular polynomials posed for the factoring

For problem 3 make sure you use the “ac method”, Show the steps of this method in your work in a similar manner of the example.

Incorporate the following five math vocabulary words into your discussion. Use

**bold****font**to emphasize the words in your writing (**Do not write definitions for the words; use them appropriately in sentences describing your math work**.

Factor

GCF

Prime factors

Perfect square

Grouping

**b^3 + 49b (***Factoring completely)***a^2 + 7ab 10b^2 (***Factoring with Two Variables)***3a^2 -14a +15 (***Factor each trinomial using the ac method. Instructions for this method are below)*

**The
ac Method**

*The
first step in factoring ax^2 + bx + c with a =1 is to find two
numbers with a product of c and a sum of b. If a cancels out 1, then
the first step is to find two numbers with a product of ac and a sum
of b. This method is called the ac method. The strategy for factoring
by the ac method follows. Note that this strategy works whether or
not the leading coefficient is 1. *

*How
to factor the trinomial ax^2 + bx + c: *

*Find two numbers that have a product equal to ac and a sum equal to b.**Replace bx by the sum of two terms whose coefficients are the two numbers found in (1).**Factor the resulting four-term polynomial by grouping.*

**Here
is an example of #3**

*5b^2
– 13b + 6 a = 5 and c = 6, so ac = 5(6) = 30. *

* The ***factor***
pairs of 30 are 1 and 30, 2 and 15, 3 and 10, 5 and 6 *

* -3(-10)=30 while -3+(-10)= -13 so replace -13b by -3b and -10b *

*5b^2
– 3b – 10b + 6 Now factor by grouping. *

*b(5b
– 3) – 2(5b – 3) The common binomial factor is (5b – 3). *

*(5b
– 3)( b – 2) Check by multiplying it back together *

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