Chemist know that by adding a very slight excess of silver nitrate to an iodide containing solution it is possible effectively to remove all the iodide on from the sample. first, writte a balanced net ionic equation for this reaction. then, assume that a sample has a mass of 2.375 grams contains 19.3% iodide ion by mass . then, calculate the mass of silver nitrate must be used to completely precipitate all the iodide from the sample.
Thank you for the opportunity to help you with your question! the solution is as such:
AgNO3 + I-à AgI + NO3-
Now , from the above stochiometry we see that 169. 8 g of AgNO3 is required for 127 g of I-
So for the above sample we need 0.612 g of silver nitrate.
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