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a binary compound contains chromium and iodine and has a mass of 8.301 grams. if the compound contains 12.05% chromum, calculate the ,ass of odine used from the compound and its emperical formula.

Jul 30th, 2015

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total mass 8.301 

If the compound contains 12.05%  Chromium 

That means weight of chromium in the compound = 12.5/100 x 8.301 

                                             = 1 gm 

So it means the mass of iodine is 8.301gms - 1gm = 7.301gms 

2) Determine moles:

Cr ā‡’ 1 g / 51.996g/mol = 0.019 mol 

Iodine Iā‡’ 7.301/126.904 g/mol = 0.0575 mol

Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 30th, 2015
This is a molar ratio of 1: 3 ratio between Cr and I

EMPIRICAL FORMULA 
CRI3


Jul 30th, 2015

Sorry CrI3

Jul 30th, 2015

Reference or for further reading

http://www.chemteam.info/Mole/Emp-formula-given-mass-data.html

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Jul 30th, 2015

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