The value of Ka for hydrofluoric acid , HF , is 7.20E-4 .
(Use H3O+ instead of H+.)
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HF(g) + H2O(l) ----------------
F-(aq) + H3O+(aq)
Ka = [F-] [H3O+] / [HF] [H2O]
Hence H2O is a pure liquid, so it’ll be equal to 1; then,
Ka = [F-] [H3O+] / [HF]
if you need the concentrations of the species, i'll help you out. let me know.
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