The value of Ka for hydrofluoric acid , HF , is 7.20E-4 . Write the equation fo

Chemistry
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The value of Ka for hydrofluoric acid HF , is 7.20E-4 .


Write the equation for the reaction that goes with this equilibrium constant.

(Use H3O+ instead of H+.)

++

Jul 31st, 2015

Thank you for the opportunity to help you with your question!

HF(g) + H2O(l) ---------------- F-(aq) + H3O+(aq)

Ka = [F-] [H3O+] / [HF] [H2O]

Hence H2O is a pure liquid, so it’ll be equal to 1; then,

Ka = [F-] [H3O+] / [HF]


Please let me know if you need any clarification. I'm always happy to answer your questions.
Jul 31st, 2015

if you need the concentrations of the species, i'll help you out. let me know.

Jul 31st, 2015

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