a bowling ball is dropped from a balloon tethered in place at an altitude of 1600 ft. the bowiling ball's height ( measured in feet) above ground t seconds after it is dropped is given by s(t)= -16t^2 + 1600. a camara is position at a latereal distance of 500 ft. from the base of the tether.
a) how fast is the distance between the camera and the bowling ball changing when the ball is at an altitude of 1200 ft?
b) if the camera is kept focused, how fast is the camera anfgke of elevation changing?
Thank you for the opportunity to help you with your question!
s(t)= -16t^2 + 1600.
1200 = -16t^2 + 1600
1200-1600 = .-16t^2
-400 = -16t^2
400/16 = t^2
distance changing = 500/5 = 100 ft/sec
anfgke of elevation changing will be 5 sec
please go to your home page .click on promotion who has a heart icon add my name Asim Reh
or my referral link https
://www.studypool.com/Asim Reh?aid=Asim Reh
in the open window and promote me
we both will get 10$ by study pool
promote and best me
Jul 31st, 2015
Studypool's Notebank makes it easy to buy and sell old notes, study guides, reviews, etc.