find second derivatice
Calculus

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x^3/5(10x) ^2/5
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x^3/5(10x) ^2/5
please give me the first derivative ?
then i will solve that for you
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[x^3(10x) ^2 ]^ 1/5
[x^3(x^2 +100  2x) ]^ 1/5
[x^5 +100x^3  2x^4) ]^ 1/5
first derivative
d/dx [x^5 +100x^3  2x^4) ]^ 1/5
1/5 [x^5 +100x^3  2x^4) ]^ (1/51) d/dx[x^5 +100x^3  2x^4) ]
1/5 [x^5 +100x^3  2x^4) ]^ (4/5) [5x^4 +300x^2  8x^3) ]
Now second derivative
d/dx 1/5 [x^5 +100x^3  2x^4) ]^ (4/5) [5x^4 +300x^2  8x^3) ]
using product rule of derivative
1/5 d/dx [x^5 +100x^3  2x^4) ]^ (4/5) [5x^4 +300x^2  8x^3) ]+ 1/5 [x^5 +100x^3  2x^4) ]^ (4/5) d/dx [5x^4 +300x^2  8x^3) ]
4/25 [x^5 +100x^3  2x^4) ]^ (4/5 1) [5x^4 +300x^2  8x^3) ]^2 + 1/5 [x^5 +100x^3  2x^4) ]^ (4/5) [20x^3 +600x  24x^2) ]
4/25 [x^5 +100x^3  2x^4) ]^(9/5) [5x^4 +300x^2  8x^3) ]^2 + 1/5 [x^5 +100x^3  2x^4)]^(4/5) [20x^3 +600x  24x^2) ] answer
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