How do you find the x-intercepts of the equation f(t) = -16t^2 - 64t 80?

User Generated

pnaqlv123

Mathematics

Description

I've already factored it out to f(t) = -16(t - 1)(t - 5), but I'm unsure what to do from there.

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Explanation & Answer

First there is no x in the equation. Secondly if there is, then the equation will be

f(x) = - 16(x - 1)(x - 5)

y = - 16(x - 1)(x - 5)

So

To find x intercept, we put y = 0 then

0 = - 16(x - 1)(x - 5)

(x - 1)(x - 5) = 0

x - 1 = 0     ,     x - 5 = 0

x = 1         ,        x = 5

Hence x intercepts are 1 and 5


Anonymous
Just the thing I needed, saved me a lot of time.

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