I'm not sure what to do. Could someone walk me through it?

Thank you for the opportunity to help you with your question!

for ax^2 + bx + c= 0

solution of quadratic equation

x =( - b +/- √ ( b^2 - 4 ac) ) / 2a

so here

x = ( - -12 +/- √ ( -12^2 - 4*3*2 ) ) / 2 *3

= ( 12 +/- √ ( 144 - 24 ) ) / 6

= ( 12 +/- √ ( 120) ) / 6

= ( 12 +/- √ (30*4) ) / 6

= ( 12 +/- 2√ ( 30) ) / 6

= 6 ( ( 2 +/- 1/3√ ( 30) ) /6

= ( 2 +/- 1/3√ ( 30) )

= 2 + √(30) / 3 or 2 - √ ( 30) / 3 ....................................ANSWER

so soluton

x = 2 + √(30) / 3 or 2 - √ ( 30) / 3

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