Find the area of the region enclosed by these graphs and the vertical lines

Calculus
Tutor: None Selected Time limit: 1 Day

Aug 1st, 2015

Thank you for the opportunity to help you with your question!

Since this problem tells us that we are using the vertical lines x = -1 and 1, those will be our boundaries for our definite integral:

So we will be doing the integral of ((x^2 + 5 - 1/3x^3))dx which gives us:

1/3x^3 + 5x - 1/12x^4 from -1 to 1, plugging those in we have:

[1/3(1)^3 + 5(1) - 1/12(1)^4] - [1/3(-1)^3 + 5(-1) - 1/12(-1)^4] = 

21/4 - (-65/12)

= 32/3 square units

Please let me know if you need any clarification. I'm always happy to answer your questions.
Aug 1st, 2015

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