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Equation of line passing through two points (x1, y1) & (x2,y2) is given by as per the following relation
(y-y1) = [(y2-y1)/(x2-x1) ] (x-x1).
hence (y+2) = (0+2)/(-2+3) (x+3)
or solving we get y+2 =2x+6 or 2x-y+4 =0
Slope intercept form of line equation is y = mx+c
hence we can write y = 2x+4 where m = 2 and c = 4
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