# There are 7 questions in the attached file about polar coordinates and roots need to be solved

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### Question Description

Super_Teach12
School: Cornell University

Here is the assignment :).. Allow me to me know if you have questions or need another help okay ;)

QUESTIONS:

Solution:
For ππ = π + ππ:
The polar of a complex number is: 2 = π ( πππ π + π π πππ)
π

Where π = βπ2 + π 2 and π = π‘ππβ1 (π) π > 0
π

= π‘ππβ1 (π) + 1000 π < 0, π > 00π < 0
π

=π‘ππβ1 (π) + 3600 , π > 0, π > 0
r = β(1)2 + (2)2 = β5
2

π = π‘ππβ1 (1) = π‘ππβ1 2 = 1.107
r = 63.3%
Hence, the polar for of π§1 = 1 + 2π would be β5(cos(1.107) + π sin(1.107)
The polar coordinates would be: βπ ππ¨π¬(π. πππ) , βπ π¬π’π§(π. πππ)

For ππ = βπ + ππ
r = β(β3)2 + (4)2 = β5

4

ΞΈ = π‘ππβ1 (β3) + 180
= β53.13 + 180
= 126.860 = 2.21 ππππππ
= 5(cos(126.860 ) + π sin(126. 860 ))
Hence, the polar coordinates would be: π(ππ¨π¬( πππ. πππ ) + π π¬π’π§(πππ. πππ ))
For ππ = βπ β ππ
r = r = β(5)2 + (6)2 β β25 + 36 = 7.81
β6

ΞΈ = π‘ππβ1 ( 5 ) + 180
= 50.19 + 180
= 230....

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Anonymous
awesome work thanks

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