Thank you for the opportunity to help you with your question!

a) At least one of the two numbers must be zero to obtain 0 as the product.

b) 2(x-3)(x-1)=0

from here, x=3 or 1

2x(x-3)(x-1)=0

x=0, 1 or 3 hence cubic equation

in the second question; what is different other then the solution?

in the second equation x is raised to power 3 while in the first x is raised to power 2

thank you so much

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