what will be produced by the decomposition of 3.00 g KClO3?

Chemistry
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what volume of O2 is measured at 24 degrees Celsius and 0.630 atm will be produced by the decomposition of 3.00 g KClO3? Assuming 100% yield. (R=0.08206 L atm/mol K)

2 KClO3 (s) --> 2 KCl (s) + 3 O2 (g)
Aug 5th, 2015

Thank you for the opportunity to help you with your question!

molar mass of KClO3=  122.5495

moles of  KClO3 IN 3 gm=3.0/122.5495=0.0245 moles

from the equation, moles of O2=3/2   *0.0245=0.03675

from PV=nRT

V=nRT/P  ;T=24+273=297

  =0.03675*0.08206* 297 /0.630

     =1.42168 LITRES


Please let me know if you need any clarification. I'm always happy to answer your questions.
Aug 6th, 2015

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