what volume of O2 is measured at 24 degrees Celsius and 0.630 atm
will be produced by the decomposition of 3.00 g KClO3? Assuming 100%
yield. (R=0.08206 L atm/mol K)
Thank you for the opportunity to help you with your question!
molar mass of KClO3= 122.5495
moles of KClO3 IN 3 gm=3.0/122.5495=0.0245 molesfrom the equation, moles of O2=3/2 *0.0245=0.03675from PV=nRTV=nRT/P ;T=24+273=297 =0.03675*0.08206* 297 /0.630 =1.42168 LITRES
moles of KClO3 IN 3 gm=3.0/122.5495=0.0245 moles
from the equation, moles of O2=3/2 *0.0245=0.03675
=0.03675*0.08206* 297 /0.630
Content will be erased after question is completed.
Enter the email address associated with your account, and we will email you a link to reset your password.
Forgot your password?