solve with elimination- nonstandard notation

label Algebra
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7x-5y=31

4x-7y=-3

Aug 7th, 2015

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7x-5y=31      (1)

4x-7y=-3       (2)

Multiply eq. (1) by 4 and eq. (2) by 7 we get,

28x-20y=124    (3)

28x-49y=-21     (4)

Subtract the eq. (3) and eq.(4) we get

29y=145

y=145/29

y=5

By putting the value of y in eq.(1) we will get the value of x

7x-5y=31      (1)

7x-5(5)=31      

7x-25=31

7x=31+25

7x=56

x=56/7

x=8

Please let me know if you need any clarification. I'm always happy to answer your questions.
Aug 7th, 2015

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