GEO105 Weather 7 discussion questions

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Question Description

(Attached) Look at the diagram above. Note that the solar declination is 15 degrees south. Now consult the analemma. What two days of the year would this diagram likely be referencing?


2)Based on the diagram, where the solar declination is at 15 degrees south, what is the ELEVATION angle for an observer at 78.7 degrees NORTH?

3)Based on the diagram, where the solar declination is at 15 degrees south, what is the ZENITH angle for an observer at 75.6 degrees north? Based on the diagram, where the solar declination is at 15 degree south, what is the ZENITH angle for an observer at 8.3 degrees south?

4)Based on the diagram, what is the minimum latitude (smallest number) in the Southern Hemisphere that receives 24 hours of daylight? ________ Keep in mind that the solar declination is at 15 degree south.

5)What is the lowest (smallest number) latitude north that would experience NO daylight on the day when the solar declination is at 15 degrees south? You can look at the diagram to estimate, but consult the formula - or just your logical thinking about sun angles, to answer the question.

6)If you are CSUN's Oviatt lawn getting your degree on May 23rd, and you look up at the sun (shade your eyes!!) - how high in the sky will the sun be on that day? Assume that CSUN is at 34.2 degrees North. Consult the analemma and answer.

7)Maybe you'll graduate in December instead! It's almost the December solstice. The sun will be much lower in the sky. What is the difference in sun angle between the solstices? Calculate the difference in elevation angle between the solstices for CSUN - assuming that CSUN is at 34.2 degrees North.No negative values.

GEO105 Weather 7 discussion questions
earth_diagram_5_15s_declination.jpg

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Tutor Answer

markjunior209
School: Carnegie Mellon University

Hello, your assignment is complete. Thank you

Surname 1
Your name
Professor’s name
Course name
Date of Submission
Geography 105
1
November 4th and February 8th
2
𝛼 = 90 + πœ‘ βˆ’ 𝛿
Where
𝛼 = π‘’π‘™π‘’π‘£π‘Žπ‘‘π‘–π‘œπ‘› π‘Žπ‘›π‘”π‘™π‘’
πœ‘ = π‘™π‘Žπ‘‘π‘–π‘‘π‘’π‘‘π‘’ π‘œπ‘“ π‘‘β„Žπ‘’ π‘™π‘œπ‘π‘Žπ‘‘π‘–π‘œπ‘›
𝛿 = π‘‘π‘’π‘π‘™π‘–π‘›π‘Žπ‘‘π‘–π‘œπ‘› π‘Žπ‘›π‘”π‘™π‘’
𝛼 = 90 + 78.7 βˆ’ 15
𝛼 = 15.7Β°
3
𝛼 = 90 + 75.6 βˆ’ 15
𝛼 = 29.4 Β°
π‘π‘’π‘›π‘–π‘‘β„Ž 𝐴𝑛𝑔𝑙𝑒 (𝜁) = 90Β° βˆ’ 𝛼
Where
𝛼 = π‘’π‘™π‘’π‘£π‘Žπ‘‘π‘–π‘œπ‘› π‘Žπ‘...

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