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Wait for calculations in a follow up . Am doing it . Thanks in advance.
solubility at 20 degrees = 34.0 gm kcl/100 gm water( from solubility tables)
in 200 gms
=34*200/100= 68gms of KCl
solubility at 50 degrees = 42.4 gm kcl/ 100gms water ( from solubility tables)
in 200 grams water
=42.4*200/100 = 84.8 grams of kcl,
since we have 80 gms of kcl, all of it is dissolved.
on cooling to 20 degrees
only 68 gm dissolves out of the total 80gms
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