# Physics lab report help

*label*Science

*timer*Asked: Feb 7th, 2019

*account_balance_wallet*$5

### Question Description

**Gravitational acceleration by using the Simple Pendulum: **

You will turn in Data table 3, P54, and Post-lab questions # 4 and 5, page56. Try to be brief and on target. You should support your answers with formulas and mathematical solution whenever possible.

Also, you will need to plot a graph either on graph paper, or on Excel for length versus period squared. Multiply the slope from the graph by 4 π^{2} to find g.

**Equation g= 4 π ^{2} ( L/T^{2})**

Compare average g from the table and g from the graph to the accepted value for g and find the % error.

You need to show the calculations for the following steps:

T(period) by dividing the total time in seconds on the number of swings

g, by using pi, length of string in meters and the period squared in seconds squared as shown in the above equation.

Find the percent error as explained above

## Tutor Answer

Attached.

Running head: ACCELERATION DUE TO GRAVITY

Name:

Date:

Class:

Assignment:

1

ACCELERATION DUE TO GRAVITY

Period (t/20)

g(experimental)

(Experimental)

Trial T = 28.6/20

g = 4π2(L/T2)

1

T=1.43

g=

4*3.142^2*(0.5/1.43^2)

g = 9.6431 m/s2

2

g(theoretical)

Percentage error of g

g = 4π2(L/T2)

Percentage Error:

𝐴𝑐𝑡𝑢𝑎𝑙 𝑣𝑎𝑙𝑢𝑒−𝐸𝑥𝑝 𝑣𝑎𝑙𝑢𝑒

g=

=

*100

𝐴𝑐𝑡𝑢𝑎𝑙 𝑣𝑎𝑙𝑢𝑒

4*3.142^2*(0.5/1.419^2)

g = 9.8057 m/s2

9.8057−9.6431

=

*100

9.8057

= 1.6582%

Trial T = 31.6/20

2

T = 1.58

g = 4π2(L/T2)

g=

4*3.142^2*(0.6/1.58^2)

g = 9.4789 m/s2

g = 4π2(L/T2)

Percentage Error:

𝐴𝑐𝑡𝑢𝑎𝑙 𝑣𝑎𝑙𝑢𝑒−𝐸𝑥𝑝 𝑣𝑎𝑙𝑢𝑒

g=

=

*100

𝐴𝑐𝑡𝑢𝑎𝑙 𝑣𝑎𝑙𝑢𝑒

4*3.142^2*(0.6/1.555^2)

g = 9.7986 m/s2

9.7986−9.4789

=

*100

9.7986

= 3.2627%

Trial T = 34.1/20

3

T =1.705

g = 4π2(L/T2)

g=

4*3.142^2*(0.7/1.705^2)

g = 9.4966 m/s2

g = 4π2(L/T2)

Percentage Error:

𝐴𝑐𝑡𝑢𝑎𝑙 𝑣𝑎𝑙𝑢𝑒−𝐸𝑥𝑝 𝑣𝑎𝑙𝑢𝑒

g=

=

*100

𝐴𝑐𝑡𝑢𝑎𝑙 𝑣𝑎𝑙𝑢𝑒

4*3.142^2*(0.7/1.679^2)

g = 9.8055 m/s2

9.8055−9.4966

=

*100

9.8055

= 3.1503%

Trial T = 36.4/20

4

T ...

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