I need to find the missing function in a quadratic equation, how do i find it?

Tutor: None Selected Time limit: 1 Day

X: 0   1     2     3        4    5    6

Y: 0  3/2   4   15/2   12    ?   24

Aug 12th, 2015

Thank you for the opportunity to help you with your question!

our equation must be in the form of y=mx^2 +xn

putting values gives

4= m4 +2n

12=16m +4n




y=x^2 +-x

y=5^2 -5


Please let me know if you need any clarification. I'm always happy to answer your questions.
Aug 12th, 2015

Let me clarify it better. There was a time limit I had to beat

Aug 12th, 2015

that would be greatly appriciated

Aug 12th, 2015

NB: This is the correct answer.ignore the first

I had forgotten to consider c

quadratic equation is in the form 

y=mX^2 +nx +c

substituting value given above gives

4 =4m+2n +c

12 =16m +4n +c

1.5 =m+n+c  using this c= 1.5 -m-n

taking eq 1 and 2

4 =4m+2n +1.5 -m-n

12=16m +4n+1.5-,m-n

the equations become

2.5 =3m+n

10.5 =15m +3n

solving the above through elimination

3(2.5=3m+n)  -

10.5 =15m+3n




c= 1.5-1/2 -1 =0

our quadratic equation should be

y =1/2x^2 +x

so to get the value when x is 5 we just substitute

y =1/2(5^2) + 5

= 17.5

Aug 12th, 2015

I hope it is now okay

Aug 12th, 2015

Did you know? You can earn $20 for every friend you invite to Studypool!
Click here to
Refer a Friend
Aug 12th, 2015
Aug 12th, 2015
Feb 20th, 2017
Mark as Final Answer
Unmark as Final Answer
Final Answer

Secure Information

Content will be erased after question is completed.

Final Answer