X: 0 1 2 3 4 5 6
Y: 0 3/2 4 15/2 12 ? 24
Thank you for the opportunity to help you with your question!
our equation must be in the form of y=mx^2 +xn
putting values gives
4= m4 +2n
Let me clarify it better. There was a time limit I had to beat
that would be greatly appriciated
NB: This is the correct answer.ignore the first
I had forgotten to consider c
quadratic equation is in the form
y=mX^2 +nx +c
substituting value given above gives
4 =4m+2n +c
12 =16m +4n +c
1.5 =m+n+c using this c= 1.5 -m-n
taking eq 1 and 2
4 =4m+2n +1.5 -m-n
the equations become
10.5 =15m +3n
solving the above through elimination
c= 1.5-1/2 -1 =0
our quadratic equation should be
y =1/2x^2 +x
so to get the value when x is 5 we just substitute
y =1/2(5^2) + 5
I hope it is now okay
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