How do I solve this problem

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The tens digit is a multiple of 5 the hundreds digit is 1 less than the tens digit the ones digit is less than the hundreds digit the sum of the digit is a multiple of 6

Aug 13th, 2015

Thank you for the opportunity to help you with your question!

let the number be xyz

y is a multiple of 5 hence it is either 5 or 0

y=x+!

z is less than x

So y must be 5 since x can not be -1

so x=4

x+Y+z should give a multiple of 6

4+5=9

the nearest multiple of 6 from 9 is 12

so z=3

The number is thus =453

Please let me know if you need any clarification. I'm always happy to answer your questions.
Aug 13th, 2015

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Aug 13th, 2015
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Aug 13th, 2015
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