Help on #1 a b c I really need help and I hope you guys help me get a better understanding
Algebra

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Since A is between B and C then clearly we can see that the distance BC would be equal to the distance BA plus the distance AC. So we would have the following expression:
BC = BA + AC
So the problem says: AB = 4x  3 ; BC = 7x + 5 ; AC = 5x  16
Then we need to enter 4x  3 in place of AB, 7x + 5 in place of BC, and 5x  16 in place of AC into the above equation. So we would have the following:
BC = BA + AC > 7x + 5 = 4x  3 + 5x  16
So we need to solve the above equation for x like this.
7x + 5 = 4x  3 + 5x  16 > 7x + 5 = 4x + 5x  3  16 > 7x + 5 = 9x  19
7x + 5 = 9x  19 > 7x  7x + 5 = 9x  7x  19 > 0 + 5 = 2x  19
5 = 2x  19 > 5 + 19 = 2x  19 + 19 > 24 = 2x + 0 > 24 = 2x
24 = 2x > 24/2 = 2x/2 > 12 = x > x = 12
Finally, we enter the obtained x value (x = 12) into the equations of AB, BC, and AC. So we have:
AB = 4x  3 > AB = 4(12)  3 > AB = 48  3 > AB = 45
BC = 7x + 5 > BC = 7(12) + 5 > BC = 84 + 5 > BC = 89
AC = 5x  16 > AC = 5(12)  16 > AC = 60  16 > AC = 44
Final answer: AB = 45 ; BC = 89 ; AC = 44
Omg thank you so much would you also mind helping me with the others please
I've done two can you help with the others
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