solve for c a^2=4 b=3.0

Mathematics
Tutor: None Selected Time limit: 1 Day

(a4c) /(b2(-2)4) = 2.0 and a2 = 4 and b=3.0


Solve for c

Aug 21st, 2015

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(a^4c) /(b^2(-2)^4) = 2.0

((a^2)^2 c) /(b^2*16) = 2.0

substitute a^2 = 4 and b=3.0

((4)^2 c) /((3^2)  *16) = 2.0

16 c / 9*16  = 2

numerator and denominator have 16,so they can be cancelled

c / 9  = 2

c = 9*2

c= 18...........................................ANSWER


answer is c = 18



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Aug 21st, 2015

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