(a^{4}c) /(b^{2}(-2)^{4}) = 2.0 and a^{2} = 4 and b=3.0

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Solve for c

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(a^4c) /(b^2(-2)^4) = 2.0

((a^2)^2 c) /(b^2*16) = 2.0

substitute a^2 = 4 and b=3.0

((4)^2 c) /((3^2) *16) = 2.0

16 c / 9*16 = 2

numerator and denominator have 16,so they can be cancelled

c / 9 = 2

c = 9*2

c= 18...........................................ANSWER

answer is c = 18

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