Write an equation using the curved-arrow notation for the acid-base reaction that will take place when NaH and CH3CO2H are mixed. Indicate if there can be no appreciable reaction.
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CH3COOH(aq) + NaOH(aq) = CH3COONa(aq) + H2O(l)
i will now explain how the reaction leading to the formation of the above products...
1. Ethanoate loses one hydrogen atom to form water, with the other atom coming from sodium hydroxide. (H+H+O=H2O)
2. Sodium atom was attracted to ethanoate to form Sodium ethanoate .......
be free to make follow up questions....thanks!
you can read to indicate arrows, my browser failled to make drawings..but the points should make you know what happenned
If I were to draw a curved-arrow for this reaction, where should it come from and where should it point?
Thank you so much!
The arrow should begin at the first H pointing to the H at the H2O, showing transfer of Hydrogen atom from sodium hydroxide to water
The second arrow shiould start at Na( sodium) atom then end at the resulting CH3COONa...
welcome...you can make me one of your tutors...always there when you need me!..thanks too!
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