##### How many different votes are possible.

label Algebra
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

There are 5 bands. Bill has to vote for his favorite, second favorite and third favorite.

Aug 23rd, 2015

In this problem, you have to choose one band as the favorite. Since there are five bands, there are five possibilities for the favorite. Now, once you have picked a band as your favorite, that only leaves four different bands as your possible second-favorite, there are four possibilities for your second place. Finally, by the same logic, there are only three bands left, or three possibilities for your third place.

The total number of possibilities is actually the product of all these, 5 x 4 x 3 = 60, because of all the mixing and matching.

Another (way longer) way of solving this problem is to try to number all possibilities. Assume the name of the bands are A, B, C, D, E. Then all possibilities for 1st, 2nd and 3rd place can be written as (with the first letter being favorite, 2nd letter second place, 3rd letter - third place)

BAC, BAD, BAE, BCA, BCD, BCE, BDA, BDC, BDE, BEA, BEC, BED and so on.

If you continue the list, you will see that there are 60 combinations. Hope this helps!

Please let me know if you need any clarification. Always glad to help!
Aug 23rd, 2015

...
Aug 23rd, 2015
...
Aug 23rd, 2015
Oct 18th, 2017
check_circle