 # CE490/590 University of South Alabama Pavement Design Homework #6 Anonymous
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University of South Alabama Department of Civil, Coastal, and Environmental Engineering CE490/590 Pavement Design Homework #6 (100 points) Due: 5:00 pm Wed Feb 20 1. A fine-grained soil has an unconfined compressive strength of 2.3 tsf. The results of repeated load testes are shown below. (1) Develop equations relating the resilient modulus to the deviator stress. (2) What should be the minimum and maximum resilient modulus for this soil? Deviater stress, psi Recoverable strain, 10-4 2 1.41 4 3.2 7 7.61 14 18.9 20 30.32 28 51.81 2. Recycled materials such as reclaimed asphalt pavement (RAP) and recycled asphalt shingles (RAS) have been used in asphalt mixtures. A contractor has designed a JMF using RAP and RAS, as attached. Please answer the following questions: (1) What are advantages and disadvantages use RAP and RAS in HMA? (2) How many stockpiles does this mix have? (3) Relying on the data in the JMF, show all the equations how to calculate air void = 4.0%, VMA = 14.9%, VFA = 73.1%, and the blended aggregate specific gravity Gsb = 2.648. (4) Show how to determine Asphalt Binder Replacement (ABR) ratio. (5) For MEPDG Level II design, we need E* input with appropriate estimation using Witczak equation. Estimate E* at each conditions below for the air void = 4%. Plot the figure with a-axis as frequency and y-axis, including temperatures, and comment on how temperature and frequency affect E*? Note: use A and VTS to calculate viscosity of asphalt at each temperature. For this binder, A = 10.3120, VTS = −3.4400. (1 Poise = 100 cP) Frequency, Temperature, Viscosity of asphalt E* (psi) Hz °F (106, Poise) 20 14 20 32 20 86 20 122 5 14 5 32 5 86 5 122 1 14 1 32 1 86 1 122 0.01 14 0.01 32 0.01 86 0.01 122

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Pavement Design

Solutions:

Problem 1

Problem 2

Pavement Design _ Homework 6
By Student’s Name
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Date

PROBLEM 1 SOLUTION
Part 1:
The Resilient Modulus is given as, y = MxC from the Resilient Modulus versus the Deviator
Stress plot. In other words, the Resilient Modulus is given as
Mr =

𝜎𝑑
𝜀𝑟

Part 2:
We have,
Deviator

Recoverable

Resilient

stress, psi

Strain, 10-4

Modulus, Mr

2

1.41

1.418

4

3.2

1.250

7

7.61

0.919

14

18.9

0.741

20

30.32

0.660

28

51.81

0.540

From the table above, a plot of Resilient Modulus vs. Deviator stress is given as,

A Plot of Resilient Modulus vs. Deviator Stress
1.6

Resilient Modulus

1.4
1.2
1
0.8
0.6
0.4
y = 1.9277x-0.368
R² = 0.9823

0.2
0
0

5

10

15

Deviator Stress

2|Page

20

25

30

The maximum Resilient Modulus is given as
= 19277 x σ-0.368 (for σ = 2)
= 19277 x 2-0.368 = 14,970 psi = 14.970 ksi.
Similarly
The minimum Resilient Modulus is given as
=19277 x σ-0.368 (for σ = 28)
= 19277 x 28-0.368 = 5,656 psi = 5.656 ksi.

PROBLEM 2 SOLUTIONS
Part 1:
The application of RAP and RAS in Hot Mix Asphalt pavements provides the following
1. The replacements of binder and aggregates r...

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Thanks, good work Brown University

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