Magnetic lab force

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Name Magnetic Force Lab Introduction: Two magnets will attract or repel depending on which poles are closest to each other. We will use these attraction and repulsion forces to develop a relationship between the amount of force and the distance between the magnets. If one magnet is laying on top of a balance, a second magnet that repels it will push it into the balance. We can determine the amount of repulsion force by converting the mass reading on the balance into the equivalent force. Purpose: The purpose of this lab is to determine the relationship between the strength of the magnetic force and the distance between two magnets. Part 1 Procedure: 1. Place a small Styrofoam cup on top of the pan of your balance. . 2. Pace a bar magnet on top of the Styrofoam cup and “tare” the balance so it reads zero. This is the "base" magnet. 3. Hold a meter stick vertically next to the balance and determine the height of the top of the magnet above the table top 4. Hold a second magnet at the 100 cm mark of the meterstick. It should be facing the first magnet in such a way that they will repel. Record the reading on the balance. We will use this reading as the "force". 5. Lower the second magnet to the 95 cm mark. Record the reading on the balance. 6. Repeat step 5 for each of the distances in your data table. 7. Repeat steps 1-6 using an attraction force. Data: cm Height from table to top of “base” magnet = 45 Repulsion Force 67.61 Force Distance Force (g) Distance (cm) (m) 50.5 Meter Stick Mark (cm) 100 95 90 85 80 75 70 65 60 go go 80 ugos Dolclor Meter Stick Mark (cm) 55 50 45 40 35 30 25 20 15 دیوید 35. 0 04 4 Par Attractive Force Force (g) Distance (cm) Force (g) Distance (m) a Meter Stick Mark (cm) 100 95 90 85 80 75 70 65 60 oss gos Iss Jo.5 Meter Stick Mark (cm) 55 50 45 40 35 30 25 20 15 50,5 us. 5 Hors 35.5 D 0 305 25.5 2005 65.5 ss.5 34 q ni 5 10.6 1119 Data Analysis: Should the strength of the attractive force be equal to the strength of the repulsion force at the same distance? Explain why or why not. Was the strength of the attractive force equal to the strength of the repulsion force at the same distance? Use several data points to justify your answer. Use data from both tables to write a relationship statement about the relationship between force and distan Part 2 Procedure: 2. Place the meterstick perpendicular to the compass so that the 0 cm mark is touching the compass at East. 1. Place the compass on the floor and let it settle. Turn the compass so the needle is pointing directly North. 3. Place the north end bar magnet so the north end is facing the compass at the 100 cm mark. 4. Slowly slide the magnet toward the compass until the compass needle is deflected 5° from North. Record 5. Continue to slide the magnet toward the compass recording each 5º deflection until the compass has been the distance for the magnet and which direction the needle deflected. deflected by 90°. 6. Repeat steps 2 - 5 using the south pole of the magnet N 7 N meterstick Data Table: Distance S Distance N N Distance N S Deflection S Deflection Deflection 35 65 28 96 1 Zg 5 a 은 17 70 93.5 40 10 37 75 24,5129 45 2 15 35 32 80130 50 2 3 1915 20 LG IS 19 13 55 30.3 123 2.2 85 19 lo 25 12 90 10 962 29 30 60 Part 2 1. Draw a "Force" vs. Distance graph using the deflection as a measure of force. Do the “north” force in one color and the “south" force in another color. Force vs. Distance 90 80 70 Corce deg) 60 50 40 30 20 10 0 60 70 80 100 90 0 10 20 30 40 50 Distance (cm) Part 1 Data : Draw a Force (g) vs. Distance (cm) graph in the space below. Do each force in different colors. Draw a best fit curve for each set of data.
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