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The aquarium at Sea Critters Depot contains 140 fish. 80 of these fish are green swordtails 44 female and 36 male & 60 are orange swordtails 36 female & 24 males. A fish is randomly captured from the aquarium: (Round your answer to 4 decimal places.)

Probability the selected fish is a green swordtail?  Pobability the selected fish is male? Probability the selected fish is a male green swordtail? Probability the selected fish is either a male or a green swordtail?

Aug 28th, 2015

The desired outcome is green swordtail. There are 80 of those, in a total of 140. The probability is therefore 80/140 = 0.5714 or 57.14%

The desired outcome is a male fish. There are 36 male (from the green swordfish) plus 24 males (from the orange swordfish), so there is a total of 60 males, in a total of 140. The probability is therefore 60/140 = 0.4286 or 42.86%

The desired outcome is BOTH MALE AND GREEN, there are 36 male green fish, out of 140. Probability is 36/140 =0.2571 or 25.71%

The desired outcome is EITHER male OR green swordtail. There are 80 green fish, and there are 60 male in total. However, we are double counting, because we are considering "male green" in both of these numbers, so we actually only have 80+60-36= 104 male OR green fish, out of 140. So the probability is 104/140 = 0.7429

Please let me know if you need any clarification. Always glad to help!
Aug 28th, 2015

Thank you so much.  Can you do a couple of more?

Let [img alt="formula61.mml" src="http://ezto.mheducation.com/13252702379415437343.tp4?REQUEST=SHOWmedia&media=formula61.mml&qid=13252700727276126" height="14" width="75"> and Assume the probability that they both occur is 0.20. What is the probability of either X or Y occurring?

You take a trip by air that involves three independent flights. If there is an 71 percent chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.)

Aug 28th, 2015

Aug 28th, 2015

I sent it to you but here they are again.  Thank you so much!

 Let P(X) =0.55 and P(Y) = 0.35  Assume the probability that they both occur is 0.20.
 What is the probability of either X or Y occurring? (Round your answer to 2 decimal places.)

You take a trip by air that involves three independent flights. If there is an 71 percent chance each specific leg of the trip is on time, what is the probability all three flights arrive on time? (Round your answer to 3 decimal places.)

Aug 28th, 2015

Aug 28th, 2015

Here is the deal, I am putting some test questions out there to find a tutor I can use for the balance of the semester.  Once I have someone I will stick with them throughout the term - December.  I already have these completed with the answers and only wanted to find a tutor.  I have had bad experiences with people promising work and they miss deadlines or do a poor job.  I also have someone who needs 8 weeks of coursework for Intermediate Alg and then immediately following they will need 8 weeks of Algebra.  So basically, I am scouting.  I like your professionalism and would love to work with you but need confirmation that I can rely on you.  I can post these two questions and try to locate someone else and compare if you prefer.

Aug 28th, 2015

I completely understand where you are coming from, and I know there are a lot of people out there who try to scam you. I believe that in my work in the previous questions I showed professionalism, and very well explained answers. I unfortunately do not work for free, however. Each question here has a value, and any follow-up in this discussion is supposed to be related only to the questions I answered above. If you believe me asking for a \$1 bid to answer another question is unfair, then I certainly hope you find another tutor, and I thank you for selecting me for this question.

Aug 28th, 2015

I can do that, lol!  I was not understanding you and definitely appreciate your integrity.  I will list it and put you as the tutor.

Aug 28th, 2015

I just sent it can you confirm you received it

Aug 28th, 2015

Just put a bid in

Aug 28th, 2015

I did I sent it to you

Aug 28th, 2015

And I made a bid, you have to accept the bid

Aug 28th, 2015

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Aug 28th, 2015
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Aug 28th, 2015
Oct 21st, 2017
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