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On rearranging the given ellipse equation , we have

8(x^2+10x+25)-200+(y-3)^2-9+193=0

(x+5)^2/2 +(y-3)^2/16=1.....(1)

General equation of ellipse is

(x-h)^2/a^2+(y-k)^2/b^2=1 ...(2)

centre is(h,k),Major axis length=b ;Minor axis length=a

distance from centre to foci is d=sqrt(b^2-a^2)

On comparing equation (1) with equation(2), we have

centre is (-5,3);Major axis is 4;Minor axis is sqrt(2)

Distance from C to foci is d

where d^2=16-2=14; d=sqrt(14)

Answer in the asked format is

(-5,3),4,sqrt(2),sqrt(14)

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