A partciular gene in dogs contributes to coat color. The two alleles exhibit incomplete dominance. Dogs with genotype mm have normal pigmentation; genotype Mm leads to "dilute" pigmentation; genotype MM
produces an all-white dog. If a breeder mates a normal dog with a white
dog, what will be the genotypes and phenotypes of the puppies?
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To find out what possible genotypes can be produced from the mating of those two dogs, we can produce what called a Punnett square, which is a way to visualize the possible allele combinations. So one dog is a normal pigment dog, meaning its allele pair must be mm. The other dog is all-white, meaning that its allele pair is MM. So, the Punnett square and the possible allele pair combinations should look like this:
Notice that the only possible genotype that can be produced from that combination is Mm. The problem stated that the phenotype expressed by that genotype is "dilute" pigmentation. This means that any puppies born will have "dilute" colored coats.
So in short: All the puppies will have the Mm genotype, and they will all express the "dilute" pigmentation phenotype. I hope this helped answer your question.
Please let me know if you need any clarification. I'm always happy to answer your questions.
Aug 29th, 2015
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