CDA 3103 Computer Organization Homework #4

timer Asked: Feb 25th, 2019
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Question Description

Look at the file below and answer the questions as soon as possible.

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CDA 3103 Computer Organization Homework #4 1. Problems: 1. (9 points) find the output of the given circuit a) b) c) 2. (10 points) Construct a half adder using NAND gates. 3. (10 points) Construct a half adder using NOR gates 4. (15 points) Design a circuit that compares the two-bit integers (x1 x0 )2 and (y1 y0 )2 , returning an output of 1 when the first 2-bit number is larger and an output of 0 otherwise. 5. a) (3 points) Construct the truth table. b) (4 points) Find the output Boolean function in the canonical sum-of-product format and the canonical product-of-sum format, respectively. c) (4 points) Using K-Map to find the simplified output Boolean function. d) (4 points) Construct the circuit for the obtained Boolean function in part (c). (16 points) Complete the truth table for the following sequential circuit: X QA(t) QB(t) Next State QA(t+1) QB(t+1) 2. Submission Requirements The following requirements are for electronic submission via Canvas. โšซ Your solutions must be in a single file with a file name yourname-hw4. โšซ Upload the file by following the link where you download the homework description on Canvas. โšซ If scanned from hand-written copies, then the writing must be legible, or loss of credits may occur. โšซ Only submissions via the link on Canvas where this description is downloaded are graded. Submissions to any other locations on Canvas will be ignored.

Tutor Answer

School: University of Maryland

Hi, here is your assignment :). Let me know if you need more assessment :).

CDA 3103Computer OrganizationHomework #4
1. Problems:

(9 points) find the output of the given circuit

(๐‘ฅ + ๐‘ฆ)(๐‘ฆโ€ฒ)
= ๐‘ฅ๐‘ฆ โ€ฒ + ๐‘ฆ๐‘ฆ โ€ฒ
= ๐‘ฅ๐‘ฆ โ€ฒ + 0
= ๐’™๐’šโ€ฒ
Hence, the ๐‘‚๐‘ข๐‘ก๐‘๐‘ข๐‘ก (๐‘ฅ + ๐‘ฆ)(๐‘ฆโ€ฒ) = ๐’™๐’šโ€ฒ

(๐‘ฅ โ€ฒ ๐‘ฆ โ€ฒ )โ€ฒ
= ๐‘ฅ โ€ฒโ€ฒ + ๐‘ฆ โ€ฒโ€ฒ
Hence, the ๐‘‚๐‘ข๐‘ก๐‘๐‘ข๐‘ก (๐‘ฅ โ€ฒ ๐‘ฆ โ€ฒ )โ€ฒ = ๐’™ + ๐’š


(๐‘ฅ โ€ฒ ๐‘ฆ๐‘ง)โ€ฒ (๐‘ฅ โ€ฒ + ๐‘ฆ + ๐‘ง โ€ฒ )
= (๐‘ฅ โ€ฒโ€ฒ + ๐‘ฆ โ€ฒ + ๐‘งโ€ฒ)(๐‘ฅ โ€ฒ + ๐‘ฆ + ...

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