the stopping distance D of a particular car after the brakes are applied varies directly as the square of the speed R. If the car is traveling 60mph it can stop in 200ft. how fast can the car go and still stop in 80ft?

Thank you for the opportunity to help you with your question!

D=kR^2

so what is the constant k

D=200ft, R=60mph

k=D/R^2

k=200/(60*60)

k=200/3600

k=1/18

so lets find R when D is 80ft

80=1/18*R^2

R^2=80*18/1

R^2=1440

R=square-root of 1440

R=37.9473319mph or 37.95(2dp)

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