A country's population in 1995 was 184 million. in 2002 it was 188 million. estimate the population in 2006 using exponential growth formula. round your answer to the nearest millions?

Thank you for the opportunity to help you with your question!

184^n =188

introducing log

log (base184) 188=log 188/log184 =n

n= 1.004124

growth = X^ 1.004124

IF 1995 =n=0 and x being value of population in 1995

equation will be

184million^(1.004124(n))

in 2006 population will be

n= 11

population will be

=184^(1.004124*11)

= 3.6*10^25 million

sorry let me update it. It is wrong.

184^(x^n)= 188

if 1995 n=0

in 2002 n =7

184000000^(x^7)=188000000

log (base184000000) 188000000=log 188000000/log184000000 =x^7 = 1.00113

x^7 =1.00113

x=1.0001614

formula is thus

184000000^(1.0001614^n)

n=2006-1995=11

184000000^(1.0001614^11)= 184000000^1.001776 =190,326712.2 = 190 million

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