Algebra 2 math problem

Algebra
Tutor: None Selected Time limit: 1 Day

C-5d= -16

3c+2d= -14

Sep 1st, 2015

Thank you for the opportunity to help you with your question!

To solve this problem, you need to solve for one variable in one equation, then substitute that variable into the other equation:

1. Solve for c in the first equation:

c-5d=-16

c=5d-16

2. Plug c into the second equation, then solve for d:

3c+2d=-14

3(5d-16)+2d=-14

15d-48+2d=-14

17d=34

d=2

3.  Now plug d into either equation to solve for c:

c-5d=-16

c-5*2=-16

c-10=-16

c=-6




Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 1st, 2015

Are you studying on the go? Check out our FREE app and post questions on the fly!
Download on the
App Store
...
Sep 1st, 2015
...
Sep 1st, 2015
Dec 3rd, 2016
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer