Algebra 2 math problem

label Algebra
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C-5d= -16

3c+2d= -14

Sep 1st, 2015

Thank you for the opportunity to help you with your question!

To solve this problem, you need to solve for one variable in one equation, then substitute that variable into the other equation:

1. Solve for c in the first equation:

c-5d=-16

c=5d-16

2. Plug c into the second equation, then solve for d:

3c+2d=-14

3(5d-16)+2d=-14

15d-48+2d=-14

17d=34

d=2

3.  Now plug d into either equation to solve for c:

c-5d=-16

c-5*2=-16

c-10=-16

c=-6




Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 1st, 2015

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