I truly need help with the following algebra problems.

Mathematics
Tutor: None Selected Time limit: 1 Day

I really want to learn, looking forward to do so. Please help me! 

x+y=7

7x+8y=67

9x+21=4y

Sep 1st, 2015

Thank you for the opportunity to help you with your question!

In order to do these problems, you want to write them in standard form.

Standard form always looks like y= kx+b (where k is some number and b is some constant).

1. x+y=7 **Notice the y is in the correct place, and the 7 is in the correct place. Only the x is incorrect.

So, we must subtract x to both sides

x-x+y=-x+7

y=-x+7.

2.

7x+8y=67 **Notice the 67 is on the right side, but the 7x is not. Also, the coefficient to y is not 1**

First subtract 7x to both sides.

7x-7x+8y=-7x+67

8y=-7x+67

Divide by negative 8 to both sides to make the coefficient 1 in front of the y

y=-7/8 x+67/8


3.

9x+21=4y **the only issue with this problem is the coefficient of 4 in front of the y**

Divide by four

y=9/4x+21/4

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 1st, 2015

For problem 2, I meant to say divide by 8 **NOT** by negative 8.

Sep 1st, 2015

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