Trying to solve this last equation :(

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x+4y=27  

Sep 1st, 2015

Thank you for the opportunity to help you with your question!

Have to put this into standard form.

Standard form is y=kx+b (where k is some constant and b is some constant)

x+4y=27 **note** x is in the wrong position and the coefficient of y is not 1

So, subtract x from both sides

x-x+4y=-x+27

4y=-x+27

Divide by 4

y=-x/4+27/4

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 1st, 2015

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