In a particular titration experiment a 25.0 ml sample of an unknown diprotic acid required 15.0 ml of 0.200 M NaOH for the end point to be reached. What is the concentration of the acid?
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Molarity(Acid) x Volume(Acid) = Molarity(Base) x Volume(Base) Fill in the equation with the known data: Vol(Acid) = 25mL Vol(Base) = 15mL Molarity(Base) = 0.200M NaOH
Molarity(Acid) x Volume(Acid) = Molarity(Base) x Volume(Base)
Molarity(Acid) x25= 0.200x15
Molarity(Acid)= 0.120 M.
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