In a particular titration experiment

Chemistry
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In a particular titration experiment a 25.0 ml sample of an unknown diprotic acid required 15.0 ml of 0.200 M NaOH for the end point to be reached.  What is the concentration of the acid?

0.167 M

0.240 M

0.0600 M

0.0159 M

Sep 1st, 2015

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Molarity(Acid) x Volume(Acid) = Molarity(Base) x Volume(Base) 

Fill in the equation with the known data: 
Vol(Acid) = 25mL 
Vol(Base) = 15mL 
Molarity(Base) = 0.200M NaOH 

Molarity(Acid) x Volume(Acid) = Molarity(Base) x Volume(Base) 

Molarity(Acid) x25= 0.200x15

Molarity(Acid)= 0.120 M.


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Sep 1st, 2015

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