##### In a particular titration experiment

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In a particular titration experiment a 25.0 ml sample of an unknown diprotic acid required 15.0 ml of 0.200 M NaOH for the end point to be reached.  What is the concentration of the acid?

0.167 M

0.240 M

0.0600 M

0.0159 M

Sep 1st, 2015

The equation you are looking for  is v1m1 =  v2m2

Therefore,   25 ml  *  M1 =  15 ml * .200 ml

Step one

Multiply the right side ( 15ml * .200ml)

25 ml * M1  =    3 ml

Step two

Divide each side by 25ml

120%

.200 x 120% = .240

Sep 1st, 2015

I need to talk to you about this question. Are you sure you wrote it down correctly?

Sep 1st, 2015

15ml * .200 =  3 ml

3ml / 25 =  .120 M

That is none of the answer choices provided, I misread the problem earlier.

Sep 1st, 2015

So the answer is .120 or .240?  The .240 is an option on my multiple choice homework but not the .120.

Sep 1st, 2015

After submitting the assignment it turns out the answer is .0600 M so I am still confused about how to solve this problem.

Sep 1st, 2015

I understand. I have contacted my professor to help elborate;however, after discussing the question with my peers and using the equation required (vm=m1m1), we picked the same answer.

Sep 1st, 2015

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Sep 1st, 2015
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Sep 1st, 2015
May 26th, 2017
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