label Algebra
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Sep 2nd, 2015

For this problem, you will need to combine 'like' terms, so add the two numbers with 'x', and add the two numbers without x.  Might be easier seeing them grouped together:

(12x + 3x) + (17-26)   Now you add both of these.

15x - 9                          From here, you can see that both terms have '3' in common, so factor out a '3'.

3(5x - 3)

Note: I'm not sure if this problem is supposed to be set to equal zero or not?  If it is, then here's the rest of the problem:

3(5x -3) = 0   Divide each side by '3'.

5x-3=0

5x=3

x=3/5

Please let me know if you have any questions and I would be happy to clarify anything for you :)

Sep 2nd, 2015

i dont get the way you did it. can you solve it a different way

Sep 2nd, 2015

Yup, I'll try to clear things up for you!

12x+17-26+3x

When you have an 'x' variable in two of the terms, you can add those together, but not with terms that don't have an 'x'.

Might be easier first if you perform the calculation first (17-26) to simplify things:

12x-9+3x

Now, you can add the 'x' terms together, simply by adding the constants attached to them.

15x-9

Does that make anymore sense?  If not, where are you getting stuck? :)

Sep 2nd, 2015

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Sep 2nd, 2015
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Sep 2nd, 2015
Oct 20th, 2017
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