##### dimensionally consistent.

label Physics
account_circle Unassigned
schedule 1 Day
account_balance_wallet \$5

The period of a simple pendulum, defined as the time necessary for one complete oscillation, is measured in

T=2[pie][Squareroot] l/g

Where l is the length of the pendulum and g is the acceleration due to gravity, in units of length divided by time squared. Show that this equation is dimensionally consistent.

Sep 2nd, 2015

Thank you for the opportunity to help you with your question!

t = 2* pie * sqrt (l/g)

t is in seconds.

pie is a number without any unit

l is in feet or meters.

g is in feet/sec^2 or meter/sec^2

l/g is in feet/(feet/sec^2) or in meter/(meter/sec^2)

so l/g is in sec^2

sqrt(l/g) is in sec.

2*pie *sqrt(l/g) is in sec or second

so both left hand side and right hand side are in second

Hence the equation is dimensionally consistent

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 2nd, 2015

...
Sep 2nd, 2015
...
Sep 2nd, 2015
Oct 20th, 2017
check_circle
Mark as Final Answer
check_circle
Unmark as Final Answer
check_circle
Final Answer

Secure Information

Content will be erased after question is completed.

check_circle
Final Answer