Assume that a procedure yields a binomial distribution with a trial repeated 13

Statistics
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Assume that a procedure yields a binomial distribution with a trial repeated 13   

    times.   Use the binomial formula to find the probability that there are exactly 7

    successes, when   p = .19

    

 

       P (X = 7) =

Sep 2nd, 2015

Thank you for the opportunity to help you with your question!

The binomial formula is nCr*Ps^r*Pf^n-r,  where n is the number of trials, r is the number of successes, Ps is the probability of success, and Pf is the probability of failure.  So plugging in the values we get:

13C7*(.19)^7*(.81)^6

= .00433

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 2nd, 2015

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Sep 2nd, 2015
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Sep 2nd, 2015
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