1) (-3a^2bc)^3/18a^4b^5c^3

simplify completely. no negative exponents

2) Solve Absloute value 2m+3 minus 1 equals 11

3) 3+7(2-5)^2+9-2^3

4) (a-y)^2+2y^3-3/a if a=-3 and y=2

5) absolute value k equals 11

6) solve for m: Absloute value sign 2m +3 minus 1 equals 11

Thank you for the opportunity to help you with your question!

2) |2m+3|-1=11

|2m+3|=12

2m=12-3 or 2m=-12-3

m=9/2 or m=-15/2

m=4.5 or m=-7.5

3)3+7(2-5)^2+9-2^3

=3+7(-3)^2+9-2^3

=3+(7*9)+9-8

=3+63 +1

=67

4)(a-y)^2+2y^3-3/a if a=-3 and y=2

=(-3-2)^2+2*2^3 -3/-3

=25+16+1

=42

5)|k|=11

k=11 or k =-11

6) same as 2.

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