Algebra 2 simplify completely. No negative exponents

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1) (-3a^2bc)^3/18a^4b^5c^3

simplify completely. no negative exponents

2) Solve Absloute value 2m+3 minus 1 equals 11 

3) 3+7(2-5)^2+9-2^3

4) (a-y)^2+2y^3-3/a if a=-3 and y=2 

5) absolute value k equals 11

6) solve for m: Absloute value sign 2m +3 minus 1 equals 11

Sep 4th, 2015

Thank you for the opportunity to help you with your question!

2) |2m+3|-1=11

    |2m+3|=12

    2m=12-3    or   2m=-12-3

       m=9/2     or     m=-15/2

       m=4.5     or     m=-7.5


3)3+7(2-5)^2+9-2^3

  =3+7(-3)^2+9-2^3

  =3+(7*9)+9-8

  =3+63 +1

   =67


4)(a-y)^2+2y^3-3/a if a=-3 and y=2 

   

   =(-3-2)^2+2*2^3 -3/-3

   =25+16+1

   =42



5)|k|=11

    k=11  or k =-11



6) same as 2.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 4th, 2015

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Sep 4th, 2015
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Sep 4th, 2015
Oct 21st, 2017
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