please provide me 100 percent correct answer

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Sep 4th, 2015

Thank you for the opportunity to help you with your question!

sorry for little mistake, Thats why i ask u to re check. time is limited so it happens.

let the force exerted by smaller tug be  along x  axis direction.

Larger tug exerts 20% more force.

therefore force exerted by larger tug is 1.20x and that by smaller is x.

Force exerted by large tug vertically is 1.20x sin(35).

and that by smaller tug is xsinθ

For ship to travel due east.

the vertical components of two forces need to be zero.
x * sinθ+1.20x * sin35=0 
sinθ=-1.20*sin35 
θ=-sin^-1(1.20*sin35) 

  =sin^-1(0.68829)
=-43.49° 
as larger tug is 35 degrees north of east 
then the smaller tug must be 43.49degrees south of east


Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 4th, 2015

is the answer correct???

Sep 4th, 2015

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