Algebra 2 simplify completely. No negative exponents
Algebra

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1) (3a^2bc)^3/18a^4b^5c^3
simplify completely. no negative exponents
2) Solve Absloute value 2m+3 minus 1 equals 11
3) 3+7(25)^2+92^3
4) (ay)^2+2y^33/a if a=3 and y=2
5) absolute value k equals 11
6) solve for m: Absloute value sign 2m +3 minus 1 equals 11
Thank you for the opportunity to help you with your question!
1.= (27a^6 b^3c^3)18a^4b^5c^3
=1.5a^2b^2
=1.5a^2/b^2
2. alternative 1
2m+31=11
2m=112
m=4.5
alternative 2
2m31=11
2m=11+4
m=7.5
m=4.5 or m=7.5
3. 3+7(25)^2+92^3
=3+7(9)+98
=3+63+1 =67
4. (ay)^2+2y^33/a if a=3 and y=2
=(1)^2 +8(8) +1
=1+64+1 =66
5 k=11 or k=11
6. same as 2 above
Thank you for the opportunity to help you with your question!
1.= (27a^6 b^3c^3)18a^4b^5c^3
=1.5a^2b^2
=1.5a^2/b^2
2. alternative 1
2m+31=11
2m=112
m=4.5
alternative 2
2m31=11
2m=11+4
m=7.5
m=4.5 or m=7.5
3. 3+7(25)^2+92^3
=3+7(9)+98
=3+63+1 =67
4. (ay)^2+2y^33/a if a=3 and y=2
=(5)^2 +8(8) +1
=25+64+1 =90
5 k=11 or k=11
6. same as 2 above
Ignore previous
answer is below
1.= (27a^6 b^3c^3)18a^4b^5c^3
=1.5a^2b^2
=1.5a^2/b^2
2. alternative 1
2m+31=11
2m=112
m=4.5
alternative 2
2m31=11
2m=11+4
m=7.5
m=4.5 or m=7.5
3. 3+7(25)^2+92^3
=3+7(9)+98
=3+63+1 =67
4. (ay)^2+2y^33/a if a=3 and y=2
=(5)^2 +2(8) +1
=25+16+1 = 42
5 k=11 or k=11
6. same as 2 above
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