Pre-calculus Question

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How do I do this? Thank you for your help in advance!

2x2 - 4x + 6 = 0 by completing the square.

Sep 6th, 2015

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Our problem


First notice that each of the coefficients are divisible by 2. So first divide by 2


Now, move the 3 from the left hand side, to the right hand side. Since on the left is addition, we need to subtract the three from both sides


Next, you divide the coefficient in front of the x term, and then square it

Our coefficient is -2.

(-2/2)^2= 1

Therefore, we add 1 to both sides


Now, we find multiples of 1 that will give add up to -2.

Well -1x-1=1, and -1+-1=-2. Therefore


Square root both sides

x-1= square root of -2 (which is not possible so....)

x-1= +/- square root of -1 multiplied by 2

x-1=  i +/- multiplied by square root of 2

x=i multiplied by +/-square root of 2 +1

Remember, that i means it is an imaginary number!

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Sep 6th, 2015

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Sep 6th, 2015

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