In a slap shot a hockey player accelerates the puck from a velocity of 5.00 m/s

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Wnk19930414

Science

Description

In a slap shot a hockey player accelerates the puck from a velocity of 5.00 m/s to 60.0 m/s in the same direction. If this takes 3.33 ✕ 10-2 s, calculate the distance over which the acceleration acts.

 m

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Explanation & Answer

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Average velocity= displacement /time

velocity= 60m/s – 5m/s= 55m/s

time = 3.33x10-2 s

distance=?

Distance= ∆velocity x time

=55 x 3.33x10-2

=1.8315m


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