A bicycle racer sprints at the end of a race to clinch a victory. The racer has an initial velocity of 12.5 m/s and accelerates at the rate of 0.550 m/s2 for 7.00 s.
(a) What is his final velocity? m/s (b) The racer continues at this velocity to the finish line. If he was 300 m from the finish line when he started to accelerate, how much time did he save? s (c) One other racer was 5.00 m ahead when the winner started to accelerate, but he was unable to accelerate and traveled at 12.7 m/s until the finish line. How far ahead of him (in meters and in seconds) did the winner finish? distance m time s
Thank you for the opportunity to help you with your question!
a) V1 = Vo + a*t =12.5 + 0.550*7 =
m/s distance = 12.5*7 + 0.275*7^2 = 100.975 m.
b) d = V1*T2 = 300-100.975 =
16.35*T2 = 199.025
T1+T2 = 7 + 12.17278 =
s. To travel 300 m with acceleration.
d = Vo*T3 = 300 m.
12.5*T3 = 300.
T3 = 24 s. To travel 300 m without accelerating.
T = T3-(T1+T2) = 24 - 19.17278 =
I will post the last part soon
Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 8th, 2015
d = V*T = 300-5 = 295 m.
12.7 * T = 295.
s. To finish.
s. Behind the winner.
300m/19.17278s * 4.05557s. =
m. Behind the