A student drove to the university from her home and noted that the odometer on h

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A student drove to the university from her home and noted that the odometer on her car increased by 16.0 km. The trip took 18.0 min.
(a) What was her average speed?
 km/h 
(b) If the straight-line distance from her home to the university is 10.3 km in a direction 25.0° south of east, what was her average velocity?
 km/h (25° S of E) 
(c) If she returned home by the same path 7 h 30 min after she left, what were her average speed and velocity for the entire trip?
average speed
 km/h 
average velocity 
 km/h
Sep 8th, 2015

Thank you for the opportunity to help you with your question!

a) average speed =16/18 min   =16/0.3  = 53.33 km /hr



b)average velocity =average displacement/time

                               =10.3 /0.3

                               =34.33 km/hr


c) average speed =16+16/7.5 =32/7.5  = 4.26 km/hr

  average velocity = 0/ 7.5 =0

since her resultant position is same.

Please let me know if you need any clarification. I'm always happy to answer your questions.
Sep 8th, 2015

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